Donald Trump leads a new Iowa poll, which reinforces the idea of his likely reelection in the 2020 Presidential Election. The new poll, conducted by Emerson College and NBC10 Boston, shows Trump with a six-point lead over his nearest challengers, his daughter Ivanka Trump and former ambassador Nikki Haley, who are tied for second place.
The poll found that, if the election was held today, 42 percent of likely Iowa voters would choose Trump, 36 percent would choose Haley, and 36 percent would choose Ivanka Trump. This poll is the first since the Iowa caucuses, and it seems to reflect the recent state of the race as a whole, with Trump maintaining the lead.
Haley, who is rumored to be considering a Presidential run in 2024, has surged in the polls since her endorsement of Donald Trump in August. She is now solidly positioned in the race, and her presence could put a dent in the Trump campaign’s Iowa support.
While Trump still holds a comfortable lead, it should be noted that Iowa is not a battleground state, so it is unlikely to make a huge impact in the general election. It does, however, provide a window into what the presidential race will look like in the coming months.
At this point, it appears that Trump is in a very strong position to win the 2020 election. The Emerson College/NBC10 Boston poll is just the latest example of this, and further reinforces the idea that Trump will be the clear favorite in November.
Rival candidate Rep. Ron DeSantis is also polling well in Iowa, registering 13 percent, and is showing strength particularly among independent voters. The Republican Congressman is hoping to build momentum in Iowa and other key states, though it may be too early to tell how he will fare in the actual election.
Overall, the Emerson College and NBC10 Boston poll shows that Iowa’s Republicans are still favor of Donald Trump. While there is still a long road ahead, and anything can happen between now and November, it does appear that the Republican nominee is well-positioned to win the state’s electoral votes.